{"id":4420,"date":"2024-08-13T00:47:11","date_gmt":"2024-08-13T00:47:11","guid":{"rendered":"https:\/\/domath.surju.ee\/?page_id=4420"},"modified":"2024-12-30T18:47:50","modified_gmt":"2024-12-30T18:47:50","slug":"surface-area","status":"publish","type":"page","link":"https:\/\/domath.surju.ee\/el\/surface-area\/","title":{"rendered":"\u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd"},"content":{"rendered":"

\u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/strong><\/span><\/h1>\n

\u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/strong> <\/span>\u03b5\u03af\u03bd\u03b1\u03b9 \u03b7 \u03c3\u03c5\u03bd\u03bf\u03bb\u03b9\u03ba\u03ae \u03c0\u03b5\u03c1\u03b9\u03bf\u03c7\u03ae \u03c4\u03b7\u03c2 \u03b5\u03c0\u03b9\u03c6\u03ac\u03bd\u03b5\u03b9\u03b1\u03c2 \u03b5\u03bd\u03cc\u03c2 \u03c4\u03c1\u03b9\u03c3\u03b4\u03b9\u03ac\u03c3\u03c4\u03b1\u03c4\u03bf\u03c5 \u03b1\u03bd\u03c4\u03b9\u03ba\u03b5\u03b9\u03bc\u03ad\u03bd\u03bf\u03c5 \u03ba\u03b1\u03b9 \u03bc\u03b5\u03c4\u03c1\u03b9\u03ad\u03c4\u03b1\u03b9 \u03c3\u03b5 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac.<\/strong>\"\"<\/p>\n

https:\/\/en.wikipedia.org\/wiki\/File:Area_conversion_-_square_mm_in_a_square_cm.png<\/a><\/p>\n

\u039c\u03b5\u03c4\u03c1\u03b7\u03c4\u03b9\u03ba\u03ad\u03c2 \u03bc\u03bf\u03bd\u03ac\u03b4\u03b5\u03c2 – \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/strong><\/span><\/p>\n

1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03bc\u03ad\u03c4\u03c1\u03bf = 10 000 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03b5\u03ba\u03b1\u03c4\u03bf\u03c3\u03c4\u03ac, cm2<\/sup>
\n1 \u03b5\u03ba\u03c4\u03ac\u03c1\u03b9\u03bf = 10 000 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03bc\u03ad\u03c4\u03c1\u03b1, m2<\/sup>
\n1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03c7\u03b9\u03bb\u03b9\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf= 100 \u03b5\u03ba\u03c4\u03ac\u03c1\u03b9\u03b1, 
\n1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03bc\u03ad\u03c4\u03c1\u03bf = 100 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03b4\u03b5\u03ba\u03b1\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03b1, dm2<\/sup>
\n1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03b4\u03b5\u03ba\u03b1\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf = 100 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03b5\u03ba\u03b1\u03c4\u03bf\u03c3\u03c4\u03ac, cm2<\/sup>
\n1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03b5\u03ba\u03b1\u03c4\u03bf\u03c3\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf = 100 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03c7\u03b9\u03bb\u03b9\u03bf\u03c3\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03b1, mm2<\/sup><\/p>\n

\u03a4\u03cd\u03c0\u03bf\u03b9 \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/strong><\/span><\/h4>\n\n\n\n
\n
\u039a\u03cd\u03b2\u03bf\u03c2<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\"\"\"\"\"\"<\/td>\n\u0395 \u03a4\u03b5\u03c4\u03c1\u03b1\u03b3\u03ce\u03bd\u03bf\u03c5 = a2<\/sup>A = 6 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ae \u03b5\u03c0\u03b9\u03c6\u03ac\u03bd\u03b5\u03b9\u03b1 A = 6 a2<\/sup><\/strong><\/td>\n\n
a –  \u03bc\u03ae\u03ba\u03bf\u03c2 \u03b2\u03ac\u03c3\u03b7\u03c2<\/h6>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n
\u039f\u03c1\u03b8\u03bf\u03b3\u03ce\u03bd\u03b9\u03bf \u03a0\u03c1\u03af\u03c3\u03bc\u03b1<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n

\"\" \"\"<\/strong><\/h4>\n<\/td>\n

\n

A = 2lw +2wh + 2lh=<\/p>\n

= 2(lw +wh+lh)<\/strong><\/p>\n<\/td>\n

\n
l – \u03bc\u03ae\u03ba\u03bf\u03c2, w –  \u03c0\u03bb\u03ac\u03c4\u03bf\u03c2, h – \u03cd\u03c8\u03bf\u03c2<\/h6>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n
\u03a4\u03c1\u03b9\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03a0\u03c1\u03af\u03c3\u03bc\u03b1<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\"\"\"\"<\/td>\n\n

SA= LSA + 2 B<\/strong><\/p>\n

LSA = aH + bH + cH = =(a + b + c) H  = PH<\/strong><\/p>\n

\"\"<\/p>\n

A = 2 (ah\/2) + (a+b+c)H =ah+PH<\/strong><\/span><\/p>\n<\/td>\n

\n
\u0395- \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/h6>\n

B – \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03c4\u03c1\u03b9\u03b3\u03c9\u03bd\u03b9\u03ba\u03ae\u03c2 \u03c0\u03bb\u03b5\u03c5\u03c1\u03ac\u03c2, \u03b2\u03ac\u03c3\u03b7\u03c2<\/p>\n

LSA – \u03a0\u03bb\u03b5\u03c5\u03c1\u03b9\u03ba\u03cc \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/h6>\n
a – \u03bc\u03ae\u03ba\u03bf\u03c2 \u03c4\u03b7\u03c2 \u03bc\u03af\u03b1\u03c2 \u03c0\u03bb\u03b5\u03c5\u03c1\u03ac\u03c2 \u03c4\u03bf\u03c5 \u03c4\u03c1\u03b9\u03b3\u03ce\u03bd\u03bf\u03c5,<\/h6>\n
h -\u03c4\u03bf \u03bc\u03ae\u03ba\u03bf\u03c2 \u03c4\u03bf\u03c5 \u03c5\u03c8\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf\u03c5 \u03c0\u03bb\u03b5\u03c5\u03c1\u03b9\u03ba\u03ac –
\n\u0397 \u03b1\u03c0\u03cc\u03c3\u03c4\u03b1\u03c3\u03b7 \u03bc\u03b5\u03c4\u03b1\u03be\u03cd \u03c4\u03c9\u03bd \u03c4\u03c1\u03b9\u03b3\u03c9\u03bd\u03b9\u03ba\u03ce\u03bd \u03b5\u03c0\u03b9\u03c6\u03b1\u03bd\u03b5\u03b9\u03ce\u03bd. <\/h6>\n

P –  \u03a0\u03b5\u03c1\u03af\u03bc\u03b5\u03c4\u03c1\u03bf\u03c2 \u03c4\u03bf\u03c5 \u03c4\u03c1\u03b9\u03b3\u03ce\u03bd\u03bf\u03c5<\/p>\n

a, b, c – \u03c0\u03bb\u03b5\u03c5\u03c1\u03ad\u03c2 \u03c4\u03bf\u03c5 \u03c4\u03c1\u03b9\u03b3\u03ce\u03bd\u03bf\u03c5 (\u03b2\u03ac\u03c3\u03b7) <\/h6>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n
\u039d- \u03b3\u03c9\u03bd\u03bf \u03a0\u03c1\u03af\u03c3\u03bc\u03b1<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\"\"<\/td>\nSA= LSA + 2 B<\/strong>A =PH + 2B<\/td>\n\n
SA-E  – \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/h6>\n

B –   \u0392\u03ac\u03c3\u03b7 <\/p>\n

LSA – \u03a0\u03bb\u03b5\u03c5\u03c1\u03b9\u03ba\u03cc \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/h6>\n
B –  \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b2\u03ac\u03c3\u03b7\u03c2 (\u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03ba\u03b1\u03bd\u03bf\u03bd\u03b9\u03ba\u03cc\u03c5 \u03c0\u03bf\u03bb\u03cd\u03b3\u03c9\u03bd\u03bf\u03c5)
\nH<\/span> –  \u038e\u03c8\u03bf\u03c2  \u03c0\u03c1\u03af\u03c3\u03bc\u03b1\u03c4\u03bf\u03c2<\/h6>\n

P- \u03c0\u03b5\u03c1\u03af\u03bc\u03b5\u03c4\u03c1\u03bf\u03c2 \u03b2\u03ac\u03c3\u03b7\u03c2 \u03ba\u03b1\u03bd\u03bf\u03bd\u03b9\u03ba\u03bf\u03cd \u03c0\u03bf\u03bb\u03c5\u03b3\u03ce\u03bd\u03bf\u03c5<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n
\u03a4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ae \u03a0\u03c5\u03c1\u03b1\u03bc\u03af\u03b4\u03b1<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n

\"\"\"\"<\/strong><\/p>\n

\"\"\"\"<\/strong><\/p>\n<\/td>\n

\n

SA= LSA +  B<\/strong><\/p>\n

A = B + 1\/2 x P x l<\/strong><\/p>\n

P = 4a<\/strong><\/p>\n

LSA =1\/2 x P x l=<\/strong><\/p>\n

= 1\/2 x 4a x l =2al<\/strong><\/p>\n

B = a2<\/sup><\/strong><\/p>\n

Lateral surface area of a pyramid (LSA) = Sum of areas of the lateral surfaces of the pyramid<\/strong><\/b><\/p>\n<\/td>\n

\n
 SA – \u0395- \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/h6>\n

LSA – \u03a0\u03bb\u03b5\u03c5\u03c1\u03b9\u03ba\u03cc \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd
\nB -\u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b2\u03ac\u03c3\u03b7\u03c2<\/p>\n

a -\u03bc\u03ae\u03ba\u03bf\u03c2 \u03c0\u03bb\u03b5\u03c5\u03c1\u03ce\u03bd \u03b2\u03ac\u03c3\u03b7\u03c2<\/h6>\n
H –  \u03ba\u03ac\u03b8\u03b5\u03c4\u03bf \u03cd\u03c8\u03bf\u03c2, \u03cd\u03c8\u03bf\u03c2 \u03c4\u03b7\u03c2 \u03c0\u03c5\u03c1\u03b1\u03bc\u03af\u03b4\u03b1\u03c2<\/h6>\n
B – \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b2\u03ac\u03c3\u03b7\u03c2 \u03c0\u03c5\u03c1\u03b1\u03bc\u03af\u03b4\u03b1\u03c2<\/h6>\n

P –  \u03c0\u03b5\u03c1\u03af\u03bc\u03b5\u03c4\u03c1\u03bf\u03c2 \u03b2\u03ac\u03c3\u03b7\u03c2 l –  \u03bc\u03ae\u03ba\u03bf\u03c2 \u03ba\u03bb\u03af\u03c3\u03b7\u03c2 \u03c4\u03c9\u03bd \u03c0\u03bb\u03b5\u03c5\u03c1\u03ce\u03bd (\u03bc\u03ae\u03ba\u03bf\u03c2 \u03b1\u03c0’ \u03c4\u03b7 \u03b2\u03ac\u03c3\u03b7 \u03c9\u03c2 \u03c4\u03b7\u03bd \u03ba\u03bf\u03c1\u03c5\u03c6\u03ae) <\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n
\u03a4\u03c1\u03b9\u03b3\u03c9\u03bd\u03b9\u03ba\u03ae \u03a0\u03c5\u03c1\u03b1\u03bc\u03af\u03b4\u03b1<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\"\"<\/td>\n\n

SA= LSA +  B<\/strong><\/p>\n

SA = B + 1\/2 x P x l<\/strong><\/p>\n

LSA =1\/2 x P x l<\/strong><\/p>\n

Bases area  =  polygon area<\/strong><\/p>\n

Lateral surface area of a pyramid (LSA) = Sum of areas of the lateral surfaces (triangles) of the pyramid<\/strong><\/b><\/p>\n<\/td>\n

\n
SA – \u0395- \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd (surface area)<\/h6>\n

LSA – \u03a0\u03bb\u03b5\u03c5\u03c1\u03b9\u03ba\u03ae \u03b5\u03c0\u03b9\u03c6\u03ac\u03bd\u03b5\u03b9\u03b1  B – \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b2\u03ac\u03c3\u03b7\u03c2 P –  \u03a0\u03b5\u03c1\u03af\u03bc\u03b5\u03c4\u03c1\u03bf\u03c2 \u0392\u03ac\u03c3\u03b7\u03c2<\/p>\n

H -\u039a\u03ac\u03b8\u03b5\u03c4\u03bf \u03cd\u03c8\u03bf\u03c2, \u03c4\u03bf \u03cd\u03c8\u03bf\u03c2 \u03c4\u03b7\u03c2 \u03c0\u03c5\u03c1\u03b1\u03bc\u03af\u03b4\u03b1\u03c2 <\/h6>\n
a -\u03bc\u03ae\u03ba\u03bf\u03c2 \u03c0\u03bb\u03b5\u03c5\u03c1\u03ac\u03c2 \u03b2\u03ac\u03c3\u03b7\u03c2 <\/h6>\n

l (m) –  \u03bc\u03ae\u03ba\u03bf\u03c2 \u03ba\u03bb\u03af\u03c3\u03b7\u03c2  \u03c4\u03c9\u03bd \u03c0\u03bb\u03b5\u03c5\u03c1\u03ce\u03bd. \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u0392\u03ac\u03c3\u03b7\u03c2  = \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03c0\u03bf\u03bb\u03c5\u03b3\u03ce\u03bd\u03bf\u03c5 
\n<\/strong> h – \u03cd\u03c8\u03bf\u03c2 \u03c4\u03c1\u03b9\u03b3\u03ce\u03bd\u03bf\u03c5<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n
\u03a3\u03c6\u03b1\u03af\u03c1\u03b1<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\"\"<\/td>\n\n
\u0395 = 4\u03c0r<\/strong>2<\/sup><\/strong><\/h5>\n<\/td>\n
\n
 <\/h6>\n
r – \u03b1\u03ba\u03c4\u03af\u03bd\u03b1<\/h6>\n

\"\"<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\n
\u0391\u03c0\u03cc\u03bb\u03c5\u03c4\u03b1 \u03ba\u03c5\u03ba\u03bb\u03b9\u03ba\u03cc\u03c2 \u03ba\u03ce\u03bd\u03bf\u03c2<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\"\"\"\"\"\"<\/td>\n\u039f\u03bb\u03b9\u03ba\u03cc \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u039a\u03ce\u03bd\u03bf\u03c5= \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03ba\u03c9\u03bd\u03b9\u03ba\u03ae\u03c2 \u03c0\u03b5\u03c1\u03b9\u03bf\u03c7\u03ae\u03c2 + \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b2\u03ac\u03c3\u03b7\u03c2<\/strong> \"\"<\/td>\n\n
B – \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u0392\u03ac\u03c3\u03b7\u03c2<\/h6>\n
H, h – \u03ba\u03ac\u03b8\u03b5\u03c4\u03bf \u03cd\u03c8\u03bf\u03c2, \u03c4\u03bf \u038e\u03c8\u03bf\u03c2 \u03c4\u03bf\u03c5 \u03ba\u03ce\u03bd\u03bf\u03c5<\/h6>\n
r – \u03b1\u03ba\u03c4\u03af\u03bd\u03b1<\/h6>\n

\"\"<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/h5>\n\n\n\n
\n
\u039a\u03cd\u03bb\u03b9\u03bd\u03b4\u03c1\u03bf\u03c2<\/strong><\/span><\/h5>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n
\"\"\"\"<\/td>\n\n

Area = 2 \u00b7 the area of the base + <\/strong>base circumference \u00b7 height A = 2\u03c0r2<\/sup> + 2\u03c0rh<\/strong><\/p>\n<\/td>\n

\n
B –  \u03b5\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b2\u03ac\u03c3\u03b7\u03c2
\nh<\/span> –  \u03cd\u03c8\u03bf\u03c2 \u03ba\u03c5\u03bb\u03af\u03bd\u03b4\u03c1\u03bf\u03c5
\nr – \u03b1\u03ba\u03c4\u03af\u03bd\u03b1<\/h6>\n

\"\"<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"

\u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b5\u03af\u03bd\u03b1\u03b9 \u03b7 \u03c3\u03c5\u03bd\u03bf\u03bb\u03b9\u03ba\u03ae \u03c0\u03b5\u03c1\u03b9\u03bf\u03c7\u03ae \u03c4\u03b7\u03c2 \u03b5\u03c0\u03b9\u03c6\u03ac\u03bd\u03b5\u03b9\u03b1\u03c2 \u03b5\u03bd\u03cc\u03c2 \u03c4\u03c1\u03b9\u03c3\u03b4\u03b9\u03ac\u03c3\u03c4\u03b1\u03c4\u03bf\u03c5 \u03b1\u03bd\u03c4\u03b9\u03ba\u03b5\u03b9\u03bc\u03ad\u03bd\u03bf\u03c5 \u03ba\u03b1\u03b9 \u03bc\u03b5\u03c4\u03c1\u03b9\u03ad\u03c4\u03b1\u03b9 \u03c3\u03b5 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac. https:\/\/en.wikipedia.org\/wiki\/File:Area_conversion_-_square_mm_in_a_square_cm.png \u039c\u03b5\u03c4\u03c1\u03b7\u03c4\u03b9\u03ba\u03ad\u03c2 \u03bc\u03bf\u03bd\u03ac\u03b4\u03b5\u03c2 – \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd 1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03bc\u03ad\u03c4\u03c1\u03bf = 10 000 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03b5\u03ba\u03b1\u03c4\u03bf\u03c3\u03c4\u03ac, cm2 1 \u03b5\u03ba\u03c4\u03ac\u03c1\u03b9\u03bf = 10 000 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03bc\u03ad\u03c4\u03c1\u03b1, m2 1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03c7\u03b9\u03bb\u03b9\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf= 100 \u03b5\u03ba\u03c4\u03ac\u03c1\u03b9\u03b1,  1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03bc\u03ad\u03c4\u03c1\u03bf = 100 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03b4\u03b5\u03ba\u03b1\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03b1, dm2 1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03b4\u03b5\u03ba\u03b1\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf = 100 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac […]<\/p>\n

\u0394\u03b9\u03b1\u03b2\u03ac\u03c3\u03c4\u03b5 \u03c0\u03b5\u03c1\u03b9\u03c3\u03c3\u03cc\u03c4\u03b5\u03c1\u03b1… from \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd<\/span><\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_eb_attr":"","_uag_custom_page_level_css":"","footnotes":""},"categories":[],"tags":[41,40,85],"class_list":["post-4420","page","type-page","status-publish","hentry","tag-english-s","tag-estonian-t","tag-greek-epsilon"],"uagb_featured_image_src":{"full":false,"thumbnail":false,"medium":false,"medium_large":false,"large":false,"1536x1536":false,"2048x2048":false,"menu-24x24":false,"menu-36x36":false,"menu-48x48":false},"uagb_author_info":{"display_name":"Signe Reidla","author_link":"https:\/\/domath.surju.ee\/el\/author\/signe\/"},"uagb_comment_info":0,"uagb_excerpt":"\u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd \u03b5\u03af\u03bd\u03b1\u03b9 \u03b7 \u03c3\u03c5\u03bd\u03bf\u03bb\u03b9\u03ba\u03ae \u03c0\u03b5\u03c1\u03b9\u03bf\u03c7\u03ae \u03c4\u03b7\u03c2 \u03b5\u03c0\u03b9\u03c6\u03ac\u03bd\u03b5\u03b9\u03b1\u03c2 \u03b5\u03bd\u03cc\u03c2 \u03c4\u03c1\u03b9\u03c3\u03b4\u03b9\u03ac\u03c3\u03c4\u03b1\u03c4\u03bf\u03c5 \u03b1\u03bd\u03c4\u03b9\u03ba\u03b5\u03b9\u03bc\u03ad\u03bd\u03bf\u03c5 \u03ba\u03b1\u03b9 \u03bc\u03b5\u03c4\u03c1\u03b9\u03ad\u03c4\u03b1\u03b9 \u03c3\u03b5 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac. https:\/\/en.wikipedia.org\/wiki\/File:Area_conversion_-_square_mm_in_a_square_cm.png \u039c\u03b5\u03c4\u03c1\u03b7\u03c4\u03b9\u03ba\u03ad\u03c2 \u03bc\u03bf\u03bd\u03ac\u03b4\u03b5\u03c2 – \u0395\u03bc\u03b2\u03b1\u03b4\u03cc\u03bd 1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03bc\u03ad\u03c4\u03c1\u03bf = 10 000 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03b5\u03ba\u03b1\u03c4\u03bf\u03c3\u03c4\u03ac, cm2 1 \u03b5\u03ba\u03c4\u03ac\u03c1\u03b9\u03bf = 10 000 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03bc\u03ad\u03c4\u03c1\u03b1, m2 1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03c7\u03b9\u03bb\u03b9\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf= 100 \u03b5\u03ba\u03c4\u03ac\u03c1\u03b9\u03b1,  1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03bc\u03ad\u03c4\u03c1\u03bf = 100 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac \u03b4\u03b5\u03ba\u03b1\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03b1, dm2 1 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03cc \u03b4\u03b5\u03ba\u03b1\u03c4\u03cc\u03bc\u03b5\u03c4\u03c1\u03bf = 100 \u03c4\u03b5\u03c4\u03c1\u03b1\u03b3\u03c9\u03bd\u03b9\u03ba\u03ac…","_links":{"self":[{"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/pages\/4420","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/comments?post=4420"}],"version-history":[{"count":14,"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/pages\/4420\/revisions"}],"predecessor-version":[{"id":5251,"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/pages\/4420\/revisions\/5251"}],"wp:attachment":[{"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/media?parent=4420"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/categories?post=4420"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/domath.surju.ee\/el\/wp-json\/wp\/v2\/tags?post=4420"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}